dielectric constant of water is 40 , so calculate its permittivity
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It can be measured by using the formula. The permittivity of free space is the capability of a vacuum to permit the electric fields and mostly used in electromagnetism. Therefore, the required answer is – When the dielectric constant of water is 80, then its permittivity will be ε=708.32×10−12F/m.
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Answer:
It can be measured by using the formula. The permittivity of free space is the capability of a vacuum to permit the electric fields and mostly used in electromagnetism. Therefore, the required answer is – When the dielectric constant of water is 80, then its permittivity will be ε=708.32×10−12F/m.
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