Question

Two diametrically opposite points of a uniform metal ring (radius, R) are connected to the terminals of a battery. If the current drawn from the battery is 1, the magnetic induction at the centre of the ring has a magnitude
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Answer 1

Answer:

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Question



Two dimetrically opposite points of a metal ring are connected to two terminals of the left gap of metrebridge. The resistance of 11 Ω is connected in right gap. If null point is obtained at a distance of 45 cm from the left end, find the resistance of metal ring.

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Solution



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Let 2R be the resistance of the metal ring. As the diametrically opposite points are connected in the left gap.

The resistance of each half is R and these two halves are connected in parallel.

Thus resistance in left gap =(R+R)(R×R)=2RR2=2RΩ

Resistance in right gap =11Ω

l=45 cm and 100−l=100−45=55 cm

For balanced meter bridge

Resistance in the right gapResistance in the left gap=100−ll

11R/2=5545

2R=545=9

∴R=18Ω

Now resistance of ring =2R=2×18=36 Ω