Difference between a number and its positive square root is 12. Find the number. topic:Quadratic equation
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Answer:
Let the number be 'x'.
ATQ
x - √x =12 eq(1)
x - 12 = √x
square both sides
(x - 12)² = x
x² - 24x + 144 = x
x² - 25x + 144 = 0
x² -16x - 9x +144 = 0
x(x-16) -9(x-16) = 0
(x-9)(x-16)=0
x= 9,16
by putting x = 9 in eq 1 we see that only its negative root i.e -3 satisfies.
so 9 cannot be the ans.
9 -√9 = 9 - 3=6 ≠12
16 - √16 =12
So,correct ans is 16
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