Question

number of oxygen atom present in 1 gram of caco3 are
a. 6*10^23
b. 1.8 *10^23
c. 6*10^22
d. 8*10^22
answer : option b)..plz explain step by step​

Answer 1

Answer:

01 mole of calcium carbonate will contain 0. 03 moles of oxygen atoms which is equal to 0. 03×6. 02×1023=1

Explanation:

hope it helps

Answer 2

Answer:

3 atoms are there in CaCO3