Question

Difference between two numbers is 30. Twice
the greater number is less than 7 times the
smaller number by 5. Find the numbers.​

Answer 1

x = 41 and y = 11

Step-by-step explanation:

let the two no.s be x and y where x is the greater no. and y is the smaller no.

GIVEN : x - y = 30 ----- (1)

2x < 7y by 5

i.e. 2x = 7y + 5 ----- (2)

By solving equation (1) and (2)...we get

x = 41 and y = 11.

41 - 11 = 30

2(41) = 7 (11) + 5

82 = 77 +5 => 82.

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