Math, asked by whywerethreinh7293, 11 months ago

Difference of two no. Is 18 and hcf and lcm are 6 and 168 what is the sum

Answers

Answered by Anonymous
3

Answer:

a+b = 66

Step-by-step explanation:

Let the two numbers be a and b.

a - b = 18

ab = hcf(a,b) lcm(a,b) = 6 × 168 = 1008

(a+b)² = (a-b)² + 4ab = 18² + 4×1008 = 324 + 4032 = 4356 = 66²

=> a+b = ±66

=> a+b = 66, since it seems implicit here that the numbers are meant to be positive.

Answered by sreeharshbhazeen
1

Answer:

let one number be x,then the other no will be x+18

Step-by-step explanation:

product of two numbers=product of their hcf and lcm

x(x+18)=6×168

x²+18x=1008

x²+18x-1008=0

x=24,-42

if x=24 then the other no will be x+18=42

so the no.s are 24 and 42

if x= -42 then the other no will be x+18= -24

so the no.s can be 24,42 or -42,-24

sum=24+42

      =66

Similar questions