Difference of two no. Is 18 and hcf and lcm are 6 and 168 what is the sum
Answers
Answered by
3
Answer:
a+b = 66
Step-by-step explanation:
Let the two numbers be a and b.
a - b = 18
ab = hcf(a,b) lcm(a,b) = 6 × 168 = 1008
(a+b)² = (a-b)² + 4ab = 18² + 4×1008 = 324 + 4032 = 4356 = 66²
=> a+b = ±66
=> a+b = 66, since it seems implicit here that the numbers are meant to be positive.
Answered by
1
Answer:
let one number be x,then the other no will be x+18
Step-by-step explanation:
product of two numbers=product of their hcf and lcm
x(x+18)=6×168
x²+18x=1008
x²+18x-1008=0
x=24,-42
if x=24 then the other no will be x+18=42
so the no.s are 24 and 42
if x= -42 then the other no will be x+18= -24
so the no.s can be 24,42 or -42,-24
sum=24+42
=66
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