Question

Difference ofc the hundred's digit and unit's digit in a three digit number is 3. sum of the Digits is 15 and the ten's digit is 2. Find The number
the number is (825) But how? explain it.​

Answer 1

Answer:

Let the unit's place digit be x, the tenth place digit be y and the hundredth place digit be z of the three digit number

So the number will be 100z+10y+x

Now given, sum of digits =x+y+z=12......(1)

And y=2x,z=3x

Now using (1)

⇒x+2x+3x=12

⇒6x=12⇒x=2

So y=2x=4 and z=3x=6

Hence the number is =100z+10y+x=642

So the reversed number is 246

Answer 2

Answer:-

Let the digit in hundred's place be x , ten's place be y and one's place be z.

The number will be (100x + 10y + z).

Given:

The ten's digit is 2.

→ y = 2

And,

Difference between the digit at hundred's place and one's place = 3.

→ x - z = 3

→ x = 3 + z -- equation (1)

Also,

Sum of the digits = 15

→ x + y + z = 15

Putting "y = 2" and "x = 3 + z" from equation (1) we get,

→ 3 + z + 2 + z = 15

→ 2z + 5 = 15

→ 2z = 15 - 5

→ 2z = 10

→ z = 10/2

→ z = 5

Putting the value of z in equation (1) we get,

→ x = 3 + 5

→ x = 8

→ The number = 100*8 + 2*(10) + 5 = 825

Hence, the required number is 825.