Math, asked by romavsinhap9uskm, 2 months ago

differenciate
this for me plsssss​

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Answered by sandy1816
2

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y = x {e}^{ \sqrt{sinx} }  \\  \frac{dy}{dx }  = x \frac{d}{dx}  {e}^{ \sqrt{sinx} }  +  {e}^{ \sqrt{sinx} }  \frac{d}{dx} x \\  \frac{dy}{dx}  = x {e}^{ \sqrt{sinx} }  \frac{1}{2 \sqrt{sinx} } cosx +  {e}^{ \sqrt{sinx} }  \\  \frac{dy}{dx}  =  \frac{x {e}^{ \sqrt{sinx} } cosx}{ \sqrt{sinx} }  +  {e}^{ \sqrt{sinx} }

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