differenece between circumfirance and radius is
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if radius, r the circumference = 2πr
![2 \pi r - r = \sqrt[3]{ 111.5136^{3/2}}](https://tex.z-dn.net/?f=2+%5Cpi+r+-+r+%3D++%5Csqrt%5B3%5D%7B+111.5136%5E%7B3%2F2%7D%7D+ "2 \pi r - r = \sqrt[3]{ 111.5136^{3/2}}")
r = (√111.5136)/(2π-1) = 2
area = πr² = 12.57
r = (√111.5136)/(2π-1) = 2
area = πr² = 12.57
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