Math, asked by aashi1610, 1 year ago

differentation of inverse trigonometry function sin-1 (2x+3)​

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Answered by balakrishna40
0

 \frac{1}{ \sqrt{1 - (2x + 3) {}^{2} } }  \times 2

 =  \frac{2}{ \sqrt{4 {x}^{2} - 12x - 8 } }

Answered by Anonymous
4

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