Question

differentation of inverse trigonometry function sin-1 (2x+3)​

Answer 1

Answer:

Step-by-step explanation:

$y=sin^{-1}(2x+3)\\\\diff w.r.t. \;\; x\\\\\frac{dy}{dx}=\frac{1}{\sqrt{1-(2x+3)^2}}\times\frac{d}{dx}(2x+3)\\\\\frac{dy}{dx}=\frac{1}{\sqrt{8-12x-4x^2}}\times2\\\\\frac{dy}{dx}=\frac{2}{\sqrt{8-12x-4x^2}}\\\\\\\frac {d}{dx}(Sin^{-1}x)=\frac {1}{\sqrt {1-x^2}}$

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Answer 2

Answer:

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