Question

Differentiability question : Find dy/dx when y = (x^2+2x-1)^5. Find the answer by Chain's Rule. Chain's rule dy/dx = (dy/dt) × (dt/dx)​

Answer 1

Hey mate, here is ur answer

Your question is (x^2+2x-1)^5

We have to differentiate it.

We can use chain rule to solve this.

Now it seems like x^n

and the formula is n. x^(n-1)

then it will become 5 (x^2+2x-1)^4*

we have to differentiate the value which we seemed to be x that is (X^2+2x-1)

So the answer is 5(x^2+2x-1)^4*(2x+2)