differential coefficient of 1/x
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Explanation:
Instead of the quotient rule we can approach this problem in an elegant way.
I am assuming the problem to be:
What is the differential coefficient of x2x3+1.
Now let Y=x2x3+1.
Take log on both sides.
logY=log(x2)−log(x3+1)
Differentiate both sides,
1YdYdx=2 xx2−3x2x3+1.
The final answer is dYdx=x2x3+1(2 xx2−3x2x3+1
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