Question

differential of log (ax)

Answer 1

Answer :

We know that,

    log (ab) = log a + log b

$\frac{d}{dx} (log x) = \frac{1}{x}$

$\frac{d}{dx} (c) = 0$, where c is any constant

Now,

$\frac{d}{dx} \{log(ax) \} \\ \\ = \frac{d}{dx} (loga + logx) \\ \\ = \frac{d}{dx} (loga) + \frac{d}{dx} (logx) \\ \\ = 0 + \frac{1}{x} \\ \\ = \frac{1}{x}$

$\implies \boxed{ \bold{\frac{d}{dx} \{log(ax) \} = \frac{1}{x} }}$

#MarkAsBrainliest