Differentiate
2 w.r.t.
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Answered by
1
Answer:
Given,
(2a−3b−2c)(4a
2
+9b
2
+4c
2
+6ab–6bc+4ca)
=(2a−3b−2c)[(2a)
2
+(3b)
2
+(2c)2–2a×(−3b)–(−3b)×(−2c)–(−2c)×2a]
=(2a)
3
+(3b)
3
+(−2c)3−3×2a×(−3b)(−2c)
=8a
3
–21b
3
−8c
3
–36abc
Answered by
0
Answer:
Above answer is correct
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