differentiate (3x+2)(1+Sinx)(x-cosx)
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Step-by-step explanation:
Let y=x2(3x−2)4cosx
Differentiate on both sides w.r.t x
dxdy=2x(3x−2)4cosx+x2(4(3x−2)3)3cosx−x2(3x−2)4sinx
∴dxdy=x(3x−2)3[(6x−4)cosx+12xcosx−x(3x−2)sinx]
∴dxdy=x(3x−2)3[(18x−4)cosx−(3x2−2x)sinx]
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