Math, asked by aditichauhan490, 1 year ago

differentiate (7)^x+1/x​

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Answered by Ssahoo
1

Answer:

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Step-by-step explanation:

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Answered by Anonymous
3

Step-by-step explanation:

let y = 7^x + 1/x ----(a

suppose

z = 7^x ----(1

logz = 7logx

differentiating with respect to z we get

dz/z= 7dx/x

dz/dx= 7z/x

from ---(1

dz/dx= 7*7^x/x

Now from ----(a

y = z+ 1/x

differentiating with respect to X

dy/dx = dz/dx - 1/x^2

Now put the value of dx/dx = 7*7^x/x

dy/dx = 7*7^x/x - 1/x^2

dy/dx = 7^(x+1)/x - 1/x^2

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