differentiate (7)^x+1/x
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Step-by-step explanation:
let y = 7^x + 1/x ----(a
suppose
z = 7^x ----(1
logz = 7logx
differentiating with respect to z we get
dz/z= 7dx/x
dz/dx= 7z/x
from ---(1
dz/dx= 7*7^x/x
Now from ----(a
y = z+ 1/x
differentiating with respect to X
dy/dx = dz/dx - 1/x^2
Now put the value of dx/dx = 7*7^x/x
dy/dx = 7*7^x/x - 1/x^2
dy/dx = 7^(x+1)/x - 1/x^2
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