Question

differentiate 8x / x^3 with respect to x​

Answer 1

Step-by-step explanation:

Let

$y = \frac{8x}{ {x}^{3} }$

$y = \frac{8}{ {x}^{2} }$

Now Applying Power Rule

$\frac{dy}{dx} = 8( - 2{x}^{ - 2 - 1} )$

$\frac{dy}{dx} = - 16 {x}^{ - 3}$

$\frac{dy}{dx} = \frac{ - 16}{ {x}^{3} }$