Question

Differentiate between oxidation and reduction

Answer 1

Answer:

Oxidation vs. Reduction

Reduction and oxidation occur simultaneously in a type of chemical reaction called a reduction-oxidation or redox reaction.

The oxidized species loses electrons, while the reduced species gains electrons.

Despite the name, oxygen need not be present in an oxidation reaction.

Oxidation vs Reduction

Oxidation occurs when a reactant loses electrons during the reaction. Reduction occurs when a reactant gains electrons during the reaction. This often occurs when metals are reacted with acid.

Oxidation and Reduction Examples

Consider the reaction between zinc metal and hydrochloric acid.

Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)

If this reaction where broken down to the ion level:

Zn(s) + 2 H+(aq) + 2 Cl-(aq) → Zn2+(aq) + 2 Cl-(aq) + 2 H2(g)

First, look at what happens to the zinc atoms. Initially, we have a neutral zinc atom. As the reaction progresses, the zinc atom loses two electrons to become a Zn2+ ion.

Zn(s) → Zn2+(aq) + 2 e-

The zinc was oxidized into Zn2+ ions. This reaction is an oxidation reaction.

The second part of this reaction involves the hydrogen ions. The hydrogen ions are gaining electrons and bonding together to form dihydrogen gas.

2 H+ + 2 e- → H2(g)

The hydrogen ions each gained an electron to form the neutrally charged hydrogen gas. The hydrogen ions are said to be reduced and the reaction is a reduction reaction. Since both processes are going on at the same time, the initial reaction is called an oxidation-reduction reaction. This type of reaction is also called a redox reaction (REDuction/OXidation).

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Answer 2

Answer:Oxidation is the increase in oxidation number or loss of electron.

While Reduction is decrease in oxidation number or gain of election.

Explanation:we will take a suitable example for the explanation.

Nå-------->Na* + ē

Here is loss of election hence it is reduction.But if we find gain of ē in any reaction,then there will be a reduction.And oxidation number on Na is increasing from 0 to +1 .Hence, it is oxidation.