differentiate by quotient rule 2x-3/4x+5
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hello users ...
solution:-
we have given that:
let, y = (2x-3)/(4x+5)
we have to find
d(y)/dx = ? using quotient rule.
we know that :
in quotient Rule
if y = u/v
then d(y)/dx = [ v(du/dx) - u (dv/dx) ] / (v²)
And
also
d(ax+c)/dx = a
Here;
dy/dx = [ (4x+5) d(2x-3) / dx - (2x-3) d (4x+5) / dx ] / (4x+5)²
=> [ (4x+5) 2 - (2x-3) 4 ] / { (4x)²+(5)² +2*4x*5 }
=> [8x + 10 - 8x +12 ] / { 16x² + 25 + 40x}
=> 22 /(16x² + 25 + 40x) Answer
@ hope it helps :)
solution:-
we have given that:
let, y = (2x-3)/(4x+5)
we have to find
d(y)/dx = ? using quotient rule.
we know that :
in quotient Rule
if y = u/v
then d(y)/dx = [ v(du/dx) - u (dv/dx) ] / (v²)
And
also
d(ax+c)/dx = a
Here;
dy/dx = [ (4x+5) d(2x-3) / dx - (2x-3) d (4x+5) / dx ] / (4x+5)²
=> [ (4x+5) 2 - (2x-3) 4 ] / { (4x)²+(5)² +2*4x*5 }
=> [8x + 10 - 8x +12 ] / { 16x² + 25 + 40x}
=> 22 /(16x² + 25 + 40x) Answer
@ hope it helps :)
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