Math, asked by sagargaudgaon, 1 day ago

differentiate cos-1 (2coax + 3sinx/√13)
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please tell me the correct answer
because it's my first unit test paper for class 12th
don't tell me wrong answer​

Answers

Answered by senboni123456
0

Answer:

Step-by-step explanation:

We have,

\tt{y=cos^{-1}\left(\dfrac{2\,cos(x)+3\,sin(x)}{\sqrt{13}}\right)}

\tt{\implies\,y=cos^{-1}\left\{\dfrac{2}{\sqrt{13}}\,cos(x)+\dfrac{3}{\sqrt{13}}\,sin(x)\right\}}

\sf{Let\,\,\,\blue{cos(\alpha)=\dfrac{2}{\sqrt{13}}}}

\sf{\blue{\implies\,sin(\alpha)=\sqrt{1-cos^{2}(\alpha)}}}

\sf{\blue{\implies\,sin(\alpha)=\sqrt{1-\left(\dfrac{2}{\sqrt{13}}\right)^{2}}}}

\sf{\blue{\implies\,sin(\alpha)=\sqrt{1-\dfrac{4}{13}}}}

\sf{\blue{\implies\,sin(\alpha)=\sqrt{\dfrac{13-4}{13}}}}

\sf{\blue{\implies\,sin(\alpha)=\sqrt{\dfrac{9}{13}}}}

\sf{\blue{\implies\,sin(\alpha)=\dfrac{3}{\sqrt{13}}}}

Now,

\tt{\implies\,y=cos^{-1}\left\{cos(\alpha)\,cos(x)+sin(\alpha)\,sin(x)\right\}}

\tt{\implies\,y=cos^{-1}\left\{cos(\alpha-x)\right\}}

\tt{\implies\,y=\alpha-x}

\tt{\implies\,\dfrac{dy}{dx}=-1}

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