Question

differentiate cos(sin√ax + b) with respect to x​

Answer 1

Answer:

-sin(sin(ax)^1/2+b)×cos((ax)^1/2)×1/2(ax)^1/2×a

Answer 2

Step-by-step explanation:

y=sin(ax+b)y=sin⁡(ax+b)

y′=dydx−=cos(ax+b).d(ax)xy′=dydx−=cos⁡(ax+b).d(ax)x

y′=cos(ax+b).ay′=cos⁡(ax+b).a

y′=acos(ax+b)y′=acos⁡(ax+b)

Note:

d(sinx)sx=cosxd(sin⁡x)sx=cos⁡x