Question

Differentiate Coshx cosx + sinhx Sinx​

Answer 1

Answer:

jöin please

bof-sbvc-miq

Step-by-step explanation:

I split this into two integrals where I=I1+I2

I1=∫cos(x)cosh(x)dx

I2=∫sin(x)sinh(x)dx

I1=sin(x)cosh(x)−∫sin(x)sinh(x)dx

This second part is equal to I2 so does that mean that

Answer 2

,

Step-by-step explanation:

Hope it's helpful to you

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