Question

Differentiate cosx²sinx²

Answer 1

2cos^3 x * sin x - 2 sin ^3 x * cos x is the answer...

Answer 2

differentiate with respect to x
$\frac{d}{dx} ( \frac{ 2\cos( {x}^{2} ) \sin( {x}^{2} )}{2} ) = 0.5\frac{d}{dx} ( \sin(2 {x}^{2} ) )$
2SinACosA=Sin2A => we get
$0.5 \cos(2 {x}^{2} ) \frac{d}{dx} (2 {x}^{2} ) = >$
$0.5(4x)( \cos(2 {x}^{2} ) ) = 2x \cos(2 {x}^{2} )$
So the answer is
$2x \cos(2 {x}^{2} )$