Question

differentiate f(x)=e^(x^7-4x^3+x)​

Answer 1

Answer:

f'(x)= $e^({x^{7} -4x^{3}+x }) (x^{7} -4x^{3}+x )$

Differentiating again...

f''(x)= $e^{(x^{7}-4x^{3}+x) }$. $7x^{2} -12x^{2} +1$

Hope u understand.....