Question

differentiate function w.r.t x
(i) tan(2x/1 - x²)

Answer 1

Answer:

f'(x)=2sec2(x)tan(x)+2tan(x)⋅(1+tan2(x)) ... ⇒1+tan2x+tan2x=sec2x+tan2x. ⇒1+2tan2x=sec2x+tan2x. ⇒ddx(1+2tan2x). Use ddxtanx=sec2x

Step-by-step explanation: