Differentiate log (1 + x^2) with respect to tan^-1 x.
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log(1+x
2
) with respect to tan
−1
x
Let u=log(1+x
2
)
v=tan
−1
x
dx
du
=
1+x
2
2x
dx
dv
=
1+x
2
1
dx
du
dx
du
=
1+x
2
1
(1+x
2
)
2x
dv
du
=
(1+x
2
)
2x
×(1+x
2
)
dv
du
=2x
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