differentiate log(2
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Hey there,
Answer:
Answer:
ddx[log2(x)]=1xln(2)
Explanation:As we know how to differentiate ln(x) , we should change the base of the logarithm first.
The according formula to change a logarithmic expression from the base a to the base b is
loga(x)=logb(x)logb(a)
You can apply the formula as follows:
log2(x)=ln(x)ln(2)
As 1ln(2) is just a constant and the derivative of ln(x) is 1x , our derivative is:
ddx[log2(x)]=ddx[ln(x)ln(2)]=1ln(2)⋅1x=1xln(2)
Hope this helps!
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