Question

differentiate log (cosec X + cot x)

Answer 1

hi this is your answer

Answer 2

Answer:

Derivative of cosec x + cot x is$=-cosec\,x\:(cot\,x-cosec\,x)$

Step-by-step explanation:

Given function = cosec x + cot x

We have to find derivative if the  function.

$\frac{\mathrm{d}(cosec\,x+cot\,x)}{\mathrm{d} x}$

$=\frac{\mathrm{d}(cosec\,x)}{\mathrm{d} x}+\frac{\mathrm{d}(cot\,x)}{\mathrm{d} x}$

$=-cosec\,x\:cot\,x+(-cosec^2\,x)$

$=-cosec\,x\:cot\,x-cosec^2\,x$

$=-cosec\,x\:(cot\,x-cosec\,x)$

Therefore, Derivative of cosec x + cot x is $=-cosec\,x\:(cot\,x-cosec\,x)$