Differentiate
log x/x
Answers
Answered by
0
Step-by-step explanation:
Let
y
=
(
ln
x
)
x
Then taking natural logarithms on both sides,
ln
y
=
ln
(
ln
x
)
x
⇒
ln
y
=
x
ln
(
ln
x
)
Differentiating both sides,
1
y
d
y
d
x
=
ln
(
ln
x
)
+
x
ln
x
d
d
x
ln
x
⇒
d
y
d
x
=
y
[
ln
(
ln
x
)
+
x
ln
x
1
x
]
⇒
d
y
d
x
=
(
ln
x
)
x
[
ln
(
ln
x
)
+
1
ln
x
]
Answered by
1
Answer:
use divide formula
Step-by-step explanation:
x * 1/x - log x *1 / x^2
1 -log x / x^2
answer
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