Differentiate my question below
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Given
y=√(x+(√x++√x+…..up to ∞)))
i.e. y=√(x+y) …….as 1+∞= ∞
ie y²- y =x
Differentiating both side w.r.t x
We get,
2y dy/dx - dy/dx = 1
dy/dx =1 /(2y - 1)……ans
please mark it as brainliest
y=√(x+(√x++√x+…..up to ∞)))
i.e. y=√(x+y) …….as 1+∞= ∞
ie y²- y =x
Differentiating both side w.r.t x
We get,
2y dy/dx - dy/dx = 1
dy/dx =1 /(2y - 1)……ans
please mark it as brainliest
drlogeswari20:
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Worst answer i have never seen
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