Question

differentiate of 2^cos^2x​

Answer 1

Step-by-step explanation:

let z= 2^cos^2(x)

so, log z = cos^2(x) log2

1/z * dz/DX = -2cos x sin x log2

dz/DX = - sin2x z log2

put tye value of Z and get to the answer.

I hope it will help you to understand the solution ☺️☺️☺️