Question

differentiate of x2 sin x​

Answer 1

$y = {x}^{2} \sin(x) \\ \\ y = {x}^{2} \cos(x ) + \sin(x) \times 2x \\ \\ y = {x}^{2} \cos(x ) + 2x\sin(x)$

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Answer 2

Step-by-step explanation:

Explanation:

The product rule states that:

ddx(uv)=u'v+uv'

Where u and v are functions of x .

In x2sinx , we have two functions: x2 and sinx

. Since they are being multiplied together, we'll need to use the product rule to find the derivative.

Let u=x2 and v=sinx :u=x2→u'=2x

v=sinx→v'=cosx

Making necessary substitutions in the product rule, we have:

(2x)(sinx)+(x2)(cosx)

=2xsinx+x2cosx

We can't really simplify this further, so we'll leave it as our final answer.

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