Question

differentiate √secx-1) /secx+1​

Answer 1

Answer:

[sec x-1] / [sec x+1] 

y = [sec x + 1 -1 -1] / [sec x+1] 

y = 1 - 2 / [sec x+1] 

y = 1 - 2 cos x / [cos x + 1] 

dy/dx = - 2 [- sin x (1+cos x) - (- sin x) cos x] / (1+cos x)^2 

dy/dx = - 2 [- sin x - sin x cos x + sin x cos x] / (1+cos x)^2 

dy/dx = - 2 [- sin x ] / (1+cos x)^2 

dy/dx = 2 sin x / (1+cos