Question

Differentiate sin(square) (3x +1) w.r.t.X​

Answer 1

$\frac{d }{dx} {sin}^{2}(3x + 1)$

we know the rule of differentiate

$if \: \: \: \: \: \frac{d}{dx} \sin^{2} x = 2 \sin x \cos \: x \: \frac{dx}{dx} \\ \\ similrly \: \: \: \\ \\ from \: above \: equation \: \\ \\ = 2 \sin(3x + 1)cos(3x + 1) \: \frac{d}{dx} (3x + 1) \\ \\ = 2sin(3x + 1)cos(3x + 1)(3) \\ \\ = 3 \: sin \: 2(3x + 1) \: \: \: \: \: \: \: \: \: \: \: \: or \\ \\ = 6sin(3x + 1)cos(3x + 1)$

so the answer is

6 sin (3x+1) cos (3x+1)

OR

3 sin 2 (3x+1)

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