Differentiate t=square root of x+3 and find displacement in first 3 seconds?
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t= √x+3 on other side
t²=x+3
at t= 3 second
9 =x + 3
sq both sides
81 = x² + 6x + 9 differentiate with respect to x
2x + 6 = 0
2x = -6
x = -3
so displacement will be - 3
t²=x+3
at t= 3 second
9 =x + 3
sq both sides
81 = x² + 6x + 9 differentiate with respect to x
2x + 6 = 0
2x = -6
x = -3
so displacement will be - 3
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