differentiate tan^-1 (sin x-cos x/sin x+cos x)
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Steps:
1) Basically divide numerator and denominator by cos x
2)you would get 1-tanx/1+tanx inside tan inverse
3) write the 1 in numerator as tan(π/4)
4)So you would get the formula of tan(π/4-x) inside tan inverse
5)Now tan^-1[tan(π/4-x)]
6)So π/4-x
Now take derivative
answer is -1
HOPE IT HELPS
MARK AS BRAINLIEST
1) Basically divide numerator and denominator by cos x
2)you would get 1-tanx/1+tanx inside tan inverse
3) write the 1 in numerator as tan(π/4)
4)So you would get the formula of tan(π/4-x) inside tan inverse
5)Now tan^-1[tan(π/4-x)]
6)So π/4-x
Now take derivative
answer is -1
HOPE IT HELPS
MARK AS BRAINLIEST
saina1234:
I didn't get it from 3rd step can u plz solve it
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