Math, asked by kabirkhn548, 6 months ago

Differentiate the fol
s. (i) (3x² + 7)(6x +3)​

Answers

Answered by SadiyaSiddiqua
0

Step-by-step explanation:

Y=(3x^2+7)(6x^2+3)=18x^4+51x^2+21

dy/dx=(18*4)x^3+(51*2)x+0

=>dy/dx=72x^3+102x

{Just remember this thing d/dx(x^n)=nx^(n-1)}

You can also apply product rule , differentiating one function and keeping the other as constant , like

dy/dx=(6x^2+3)d/dx(3x^2+7)+(3x^2+7)d/dx(6x^2+3)

d/dx=6x^2+3(6x)+3x^2+7(12x)

d/dx=72x^3+102x

Hope this help you

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