differentiate the following w.r.t.x
3√(2x²+3+1÷x)
Answers
Answered by
1
Answer:Method 1:
Let y=(x 3 −2x−1) 5
Put u=x
3
−2x−1. Then y=u
5
∴
du
dy
=
du
d
(u
5
)=5u
4
=5(x3−2x−1)4 and
dx
du
=
dx
d
(x
3
−2x−1)
=3×2−2×1−0
=3×2−2
∴
dx
dy
=
du
dy
×
dx
du
=5(x
3
−2x−1)
4
(3x
2
−2)
=5(3x
2
−2)(x
3
−2x−1)
4
Method 2:
Let y=(x
3
−2x−1)
5
Differentiating w.r.t. x, we get
dx
dy
=
dx
d
(x
3
−2x−1)
5
=5(x
3
−2x−1)4×
dx
d
(x
3
−2x−1)
=5(x
3
−2x−1)
4
×(3x
2
−2×1−0)
=5(3x
2
−2)(x
3
−2x−1)
4
Note: Out of the two methods given above, we will use Method 2 for solving the remaining problems.
Step-by-step explanation:
please mark me as brainliest
Similar questions