differentiate the following with respect to X log x to the power 3
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Answer:
y=(logx)
x
Taking log on both sides, we get,
logy=xlog(logx)
Differentiating w.r.t x, we get,
y
1
dx
dy
=
logx
x
×
x
1
+log(logx)
dx
dy
=(logx)
x
(
logx
1
+log(logx))
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