Math, asked by mazumdarishika, 1 month ago

differentiate the function 2√cot (x^5) w.r.t x​

Answers

Answered by sandy1816
0

let  \:  \: \:  \:  \: y = 2 \sqrt{cot {x}^{5} }  \\  \\  \frac{dy}{dx}  = 2 \frac{1}{2 \sqrt{cot {x}^{5} } }  \frac{d}{dx} cot {x}^{5}  \\  \\  \frac{dy}{dx}  =  \frac{1}{ \sqrt{cot {x}^{5} } } ( -  {cosec}^{2}  {x}^{5} ) \frac{d}{dx}  {x}^{5}  \\  \\  \frac{dy}{dx} =   \frac{ -  {cosec}^{2}  {x}^{5} }{ \sqrt{cot {x}^{5} } } 5 {x}^{4}  \\  \\  \frac{dy}{dx}  =  \frac{ - 5 {x}^{4}. {cosec}^{2} {x}^{5}   }{ \sqrt{cot {x}^{5} } }

Similar questions