Math, asked by abhilashasamundre, 7 months ago

differentiate the function sin(ax+b)/cos(cx+d)​

Answers

Answered by tarracharan
2

 \frac{d}{dx} ( \frac{ \sin(ax + b) }{ \cos(cx  + d) } )\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\  =  \frac{ \frac{d}{dx}( \sin(ax + b))  \times  \cos(cx + d)  - \sin(ax + b) \times  \frac{d}{dx} (\cos(cx + d))}{\cos^{2} (cx + d)  }  \\   = \frac{a \times \cos(ax + b)  \times \cos(cx + d) - \sin(ax + b) \times c(-  \sin(cx + d)) }{  {cos}^{2} (cx + d)}

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