differentiate the function w. r. t x e^x / 1+x^2
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Let y=
(x−3)(x−4)(x−5)
(x−1)(x−2)
Taking logarithm on both the sides, we obtain
logy=log
(x−3)(x−4)(x−5)
(x−1)(x−2)
⇒logy=
2
1
log[
(x−3)(x−4)(x−5)
(x−1)(x−2)
]
⇒logy=
2
1
[log[(x−1)(x−2)]−log[(x−3)(x−4)(x−5)]]
⇒logy=
2
1
[log(x−1)+log(x−2)−log(x−3)−log(x−4)−log(x−5)]
Differentiating both sides with respect to x, we obtain
⇒
y
1
dx
dy
=
2
1
[
x−1
1
.+
x−2
1
−
x−3
1
−
x−4
1
−
x−5
1
]
⇒
dx
dy
=
2
y
(
x−1
1
+
x−2
1
−
x−3
1
−
x−4
1
−
x−5
1
)
∴
dx
dy
=
2
1
(x−3)(x−4)(x−5)
(x−1)(x−2)
[
x−1
1
+
x−2
1
−
x−3
1
−
x−4
1
−
x−5
1
]
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