differentiate the function y=log x-4x3
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Answered by
3
Answer is 1/x- 12(x^2)
you just need to differentiate log x which is 1/x
and them differentiate 4x3 which is 12x2
you just need to differentiate log x which is 1/x
and them differentiate 4x3 which is 12x2
Answered by
9
In the attachment I have answered this problem.
I have applied the following formulae to find the derivative.
1. d(logx)/dx = 1/x
2. d(x^n)/dx = n x^n-1
See the attachment for detailed solution.
I have applied the following formulae to find the derivative.
1. d(logx)/dx = 1/x
2. d(x^n)/dx = n x^n-1
See the attachment for detailed solution.
Attachments:
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