Differentiate the function
Y=log x-4x3
Log x+4x3
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Answered by
14
Answer:
Step-by-step explanation:
y = logx - 4x^{3}logx + 4x^{3}
dy/dx = 1/x - 4x^{3} logx + 4x^{3}
= 1/x - 4 ( 3x^{2} logx + x^{3} 1/x + 12 x^{2}
= 1/x - 12 x^{2} logx + 4 x^{2} + 12 x^{2}
dy/dx = 1/x - 12 x^{2} logx + 4 x^{2} + 12 x^{2}
Answered by
8
Answer:
Step-by-step explanation:
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