differentiate the sin (wt+tita)
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We have to differentiate it wrt 't'
r Omega and theta are thus constants
So, taking r as constant we first differentiate sin(ometa t - theta) which will be cos(Omega t - theta)
Now by chain rule, we differentiate omega t - theta wrt t which will be omega
Multiply the two results
dy/dt = rcos(omega t- theta) (omega
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