Math, asked by quotes0913, 8 months ago

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Answered by Anonymous
4

GIVEN:-

  • P(x)=2x⁴-5x³+2x²-x+2

  • f(x)= x²-3x+2

TO PROVE:-

  • Without actual division we have to Prove the p(x) is divisible by f(x).

CONCEPT USED:-

  • \rm\pink{Factor\:theorem}.

How To solve?

  • First we have to find the factors or zeroes of p(x) by splitting the middle term if f(x).

  • After finding the factors we have to use the factor theroem to to check if it is the zeroes of p(x) or not .

Now,

\implies\rm{x^2-3x+2}

\implies\rm{x^2-2x-x+2}

\implies\rm{x(x-2)-1(x-2)}

\implies\rm{(x-1)(x-2)}.

Hence, The factors of p(x) are (x-1) and (x-2).

Therefore,

\sf{(x-1)=0}

\sf{x=1}

Now, Put the value of x in given p(x).

\implies\sf{P(1)=2(1)^4-5(1)^3+2(1)^2-1+2}

\implies\sf{2-5+2-1+2}

\implies\sf{-3+1+2}

\implies\sf{-3+3}

\implies\sf{0}.

From this we get (x-1) is the factor of p(x).....1

Now, Similarly

\sf{(x-2)=0}

\sf{x=2}

Now, Put the value of x in given p(x).

\implies\sf{P(1)=2(2)^4-5(2)^3+2(2)^2-2+2}

\implies\sf{32-40+8}

\implies\sf{-8+8}

\implies\sf{0}

From this we get (x-2) is also the factor of p(x)...

From 1 and 2 it is proved that P(x) is exactly divisible by f(x).

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