Differentiate w.r.t x:
sin^2 x
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Answered by
8
we have
y = sin²x
on differentiating it we get ,
Refer to the attached page →
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locomaniac:
aye? my book has got the answer=> sin 2x ??
Answered by
1
Hi,
Here is your answer,
y = sin²x
Differentiate with respect to ''x''
BY CHAIN RULE,
→ dy/dx = 2sinx × cosx Formula:- sin2θ = 2sinθ × cosθ
dy/dx = sin2x { ∴ FINAL ANSWER }
Hope it helps you !
Here is your answer,
y = sin²x
Differentiate with respect to ''x''
BY CHAIN RULE,
→ dy/dx = 2sinx × cosx Formula:- sin2θ = 2sinθ × cosθ
dy/dx = sin2x { ∴ FINAL ANSWER }
Hope it helps you !
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