Question

Differentiate w.r.t x

y = ln (x^3 - sin x )

Show the required calculations

Answer 1

hi friend,

=>y =In (x³-sinx)

=>dy/dx = 1/x³-sinx. (d(x³-sinx)/dx)

=>dy/dx= 3x²-cosx/x³-sinx

I hope this will help u :)

Answer 2

we know that :-

d(lnx)/dx = 1/x

so using this rule and chain rule we can solve this ..


se attached file
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hope it will help u