Question

differentiate w.r.t.x
y=sin {log(x^3 - 1)}​

Answer 1

Answer:

cos{log(x^3-1)}/(x^3-1)

Step-by-step explanation:

y=sin{log(x^3-1)}

dy/dx= d/dxsin{log( x^3-1)}

dy/dx=cos{(logx^3-1) d/dx log(x^3-1)

=cos{logx^3-1)}×1÷(x^3-1)

= cos{log(x^3-1)}/(x^3-1)